taniabieber56 taniabieber56

25-09-2020
Mathematics

contestada

______cos b= 1/2[sin(a+b)+sin(a-b)]. A. cos a B. sin a C. cos b D. sin b

Respuesta :

25-09-2020

sin(a+b) = sinacosb + cosasinb

sin(a-b) = sinacosb - cosasinb

adding we get sin(a+b) + sin(a-b) = 2sinaccosb

so sinacosb = 1/2sin(a+b) + sin(a-b)

Answer: Sin a

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ambrown147 ambrown147

15-06-2021

Answer:

sin a

Step-by-step explanation:

A P E X

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