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A car from the beginning was traveling at 27.8m/s when he stepped on the brakes and stopped. According to the DMV, this would leave a skid mark of 60m. What is his acceleration?

Respuesta :

MathPhys

Answer:

-6.44 m/s²

Explanation:

Given:

Δx = 60 m

v₀ = 27.8 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (27.8 m/s)² + 2a (60 m)

a = -6.44 m/s²

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