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During the spin cycle of your clothes washer, the tub rotates at a steady angular velocity of 33.9 rad/s. Find the angular displacement Δθ of the tub during a spin of 92.1 s, expressed both in radians and in revolutions.

Respuesta :

Answer:

the angular displacement Δθ of the tub during a spin of 92.1s is 3122.19 rad or 496.91 rev

Explanation:

Given;

Angular velocity v = 33.9 rad/s

Time t = 92.1 s

Angular displacement d = angular velocity × time

d = vt

Substituting the given values;

d = 33.9 × 92.1 rad

d = 3122.19 rad

To revolutions;

revolution = radian/2π

d = 3122.19/2π rev

d = 496.91 rev

the angular displacement Δθ of the tub during a spin of 92.1s is 3122.19 rad or 496.91 rev

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