Respuesta :

dalendrk
[tex]A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\the\ slope:m=\dfrac{y_B-y_A}{x_B-x_A}[/tex]

[tex](-4;\ 5);\ (3;\ a);\ m=\dfrac{2}{3}\\\\subtitute:\\\\\dfrac{a-5}{3-(-4)}=\dfrac{2}{3}\\\\\dfrac{a-5}{7}=\dfrac{2}{3}\ \ \ \ \ |cross\ multiply\\\\3(a-5)=7\cdot2\\\\3a-15=14\ \  \\ |add\ 15\ to\ both\ sides\\\\3a=29\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=\frac{29}{3}}[/tex]

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