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An ice-skater pushes off from a wall and skates 20 m across the ice. The skater did 2 J of work. If the skater used twice as much force, what would happen to the work done?

Respuesta :

Answer:

The work done will also be twice the former value; 4J

Explanation:

Mathematically,

work = force x distance

W = F x d

Given;

W = 2J

d = 20m

F = ?

Hence

[tex]2= F*20\\F=\frac{2}{20}\\F=0.1N[/tex]

When the force F is twice, we have

F = 2 x 0.1

F = 0.2N

Since the distance remains constant, the new work done becomes

W = 0.2 x 20

W = 4J

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