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  • 24-03-2020
  • Physics
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what is the kinetic energy of a 74.0 kg skydiver falling at a terminal velocity of 52.0m/s?

Respuesta :

adebanjomichael44
adebanjomichael44 adebanjomichael44
  • 24-03-2020

Answer:

100,048

Explanation:

K.E = 1/2 m (v)^2

K.E = 1^/2 * 74 * (52)^2

K.E = 100,048J =100.048kJ

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