Respuesta :

Answer:

  1.25 +0.5i

Step-by-step explanation:

[tex]\dfrac{12-i}{8-4i}=\dfrac{(12-i)(8+4i)}{(8-4i)(8+4i)}=\dfrac{96+40i-4i^2}{8^2-(4i)^2}\\\\=\dfrac{100+40i}{64+16}=\boxed{1.25+0.5i}[/tex]