An iron bar has a mass of 771 g. After the bar had been standing in air for a month, exactly one-eighth of the iron turned to rust (Fe2O3). Calculate the final mass of the iron bar and the rust.

Please explain your calculations; I want to understand how to find the answer

Respuesta :

Answer:

N2(g) + 3H2(g) → 2NH3(g)

Explanation:

Balanced chemical equations only show formulae, not names. A balancing number, written in normal script, multiplies all the atoms in the substance next to it.