Answer:
0.029N
Explanation:
Pressure = displacement × density of steel × acceleration due to gravity
displacement = 0.1in = 0.1×0.0254m = 0.00254m, density of steel = 7900kg/m^3, acceleration due to gravity = 9.8m/s^2
Pressure = 0.00254×7900×9.8 = 196.65N/m^2
Force(P) = pressure × area
Area of 1 pin-connected A-36 steel member = 0.75in^2 = 4.84×10^-6m^2
Area of 3 pin-connected A-36 steel member = 3×4.84×10^-6 = 1.452×10^-5m^2
Force(P) = 196.65 × 1.4652×10^-5 = 0.0029N
