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A strings. A 50 gram bullet, traveling horzontally, strikes the block and becomes embedded inside the block. Immediately after the bullet becomes embedded in the block, the block is observed to have a speed of 8.0 m/s. What was the speed of the bullet before it hit the block?

Respuesta :

Answer:

u= 200 m/s

Explanation:

Given that

Mass of bullet ,m= 50 gm

Assume that mass of block ,M= 1.2 kg

Lets take speed of the bullet before collision = u m/s

The speed of the system after collision ,v= 8 m/s

There is no any external force ,that is why linear momentum of the system will be conserve.

Linear momentum ,P = mass x velocity

m u = (M+m)v

0.05 x u = (1.2 + 0.05 ) x 8

u= 200 m/s

Therefore the speed of the bullet just before the collision is 200 m/s.

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