The length of a rectangular room is 5 feet more than its width. The perimeter of the room is
66 feet. Let L represent the length of the room and W represent the width in feet. The system of equations
L=W + 5
can be used to represent this situation. What are the room's dimensions?
166 = 2L + 2W

Respuesta :

Answer:

[tex]\displaystyle 39 = W \\ 44 = L[/tex]

Step-by-step explanation:

{L = W + 5

{166 = 2L + 2W

166 = 2[W + 5] + 2W

166 = 2W + 10 + 2W

166 = 10 + 4W

- 10 - 10

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[tex]\displaystyle \frac{156}{4} = \frac{4W}{4}[/tex]

[tex]\displaystyle 39 = W[/tex][Plug this back into both equations above to get the length of 44 feet; [tex]\displaystyle 44 = L[/tex]

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