larrystylinsonsup
larrystylinsonsup larrystylinsonsup
  • 23-09-2019
  • Mathematics
contestada

Solve the equation.
3x^2+40=-x^2-56

Respuesta :

jimrgrant1 jimrgrant1
  • 23-09-2019

Answer:

x = ± 2i[tex]\sqrt{6}[/tex]

Step-by-step explanation:

Given

3x² + 40 = - x² - 56 ( add x² to both sides )

4x² + 40 = - 56 ( subtract 40 from both sides )

4x² = - 96 ( divide both sides by 4 )

x² = - 24 ( take the square root of both sides )

x = ± [tex]\sqrt{-24}[/tex]

  = ± [tex]\sqrt{4(6)(-1)}[/tex] → note [tex]\sqrt{-1}[/tex] = i

  = ± 2i[tex]\sqrt{6}[/tex]

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