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You are given a parallel plate capacitor that has plates of area 27 cm^2 which are separated by 0.0100 mm of nylon (dielectric constant x = 3.4). You are told to assume that this capacitor stores 011 mC of charge. Calculate what the applied voltage in kV should be for this capacitor

Respuesta :

Answer:

Applied voltage should be 13.5396 kV

Explanation:

The charge stored by a capacitor when subjected to a potential difference 'v' across it's plates is given by

[tex]Q=\frac{K\epsilon _{o} A}{d}V[/tex]

Solving for V we get

[tex]V=\frac{Qd}{K\epsilon _{o}A}[/tex]

thus to store a charge of 0.11mC we solve for V as follows

Applying values we get

[tex]V=\frac{0.11\times 10^{-3}\times 0.01\times 10^{-3}}{27\times 10^{-4}\times 3.4\times 8.85\times 10^{-12}}[/tex]

[tex]\therefore V=13.5396kV[/tex]

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