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a chemical company makes pure silver by reacting silver nitrate with Zinc. the company needs to make 800 grams of pure silver for a client. they have 599 grams of zinc and 1500 grams of silver nitrate will the make enough silver to fill the order

Respuesta :

The reaction between zinc and silver nitrate is

[tex] Zn + 2 AgNO3 \rightarrow Zn(NO3)2 + 2 Ag [/tex]

Moles of Zn = m /M = 599 /65 = 9.2 mol

Moles of AgNO3 = m /M = 1500 /169 = 8.87 mol

Silver nitrate is reacting completely to give silver

Thus, moles of Silver nitrate is equivalent to silver = 8.87

For mass of silver produced

m /M = 8.87 = m /107

m = 949.24 g

Hence, the given quantity of reactants are sufficient to produce 800 g of silver as the amount of silver produced is 949.24 g

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