From the given expression: (6x^2-54)/(5x^2-20) simplifying the above we get: [6(x^2-9)]/[5(x^2-4)] =[6(x-3)(x+3)]/[5(x+2)(x-2)] The expression will be 0 when the numerator is zero, thus given the numerator, the values that will make it 0 will be x=3 and x=-3 hence the answer is: x=-3 and x=3
