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Calculate the concentration of H2,I2
and HI at equilibrium if 0.0400 mole of HI is placed in a
1.00L flask at 430oC. Kc for the reaction:H
2(g)+I2(g)⇌2HI(g)is 54.4
at this temperature.
a. [H2][M]=0.0200[
I2][M]=0.0200[HI][M]=0.0200[
b. H2][M]=0.00427[I2][M]=0.00427[HI][M]=
0.0315
c. [H2][M]=0.0315[I2][M]=0.0315[HI][M]=0.00850
d. [H2][M]=0.000478[I2][M]=0.00478[HI][M]=0.0352

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